The position of particle is given by \(\vec{\mathrm{r}} = 2\mathbf{t}^{2}\hat{\mathrm{i}} +3\hat{\mathrm{j}} +4\hat{\mathrm{k}}\) where t is in second and the coefficients have proper units for \(\vec{\mathrm{r}}\) to be in metre. The \(\vec{a}(t)\) of the particle at \(t = 1\) s is
Choose Your Option
A. \(4\mathrm{m}\mathrm{s}^{-2}\) along y-direction
B. \(3\mathrm{m}\mathrm{s}^{-2}\) along x-direction
C. \(4\mathrm{m}\mathrm{s}^{-2}\) along x-direction
D. \(2\mathrm{m}\mathrm{s}^{-2}\) along z-direction
Solution & Explanation
No details explanation available for this question. Option C is the verified correct answer.