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QID: #29250
During complete combustion of one mole of butane, 2658 kJ of heat is released. The thermochemical reaction for above change is
Choose Your Option
A.
\(2\mathrm{C_4H_{10}(g) + 13O_2(g)\rightarrow 8CO_2(g) + 10H_2O(l)}; \Delta_c H = -2658.0\mathrm{kJmol^{-1}}\)
B.
\(\mathrm{C_4H_{10}(g) + \frac{13}{2}O_2(g)\rightarrow 4CO_2(g) + 5H_2O(g)}; \Delta_c H = -1329.0\mathrm{kJmol^{-1}}\)
C.
\(\mathrm{C_4H_{10}(g) + \frac{13}{2}O_2(g)\rightarrow 4CO_2(g) + 5H_2O(l)}; \Delta_c H = -2658.0\mathrm{kJmol^{-1}}\)
D.
\(\mathrm{C_4H_{10}(g) + \frac{13}{2}O_2(g)\rightarrow 4CO_2(g) + 5H_2O(l)}; \Delta_c H = +2658.0\mathrm{kJmol^{-1}}\)
Solution & Explanation
No details explanation available for this question. Option C is the verified correct answer.
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