During complete combustion of one mole of butane, 2658 kJ of heat is released. The thermochemical reaction for above change is
Choose Your Option
A. \(2\mathrm{C_4H_{10}(g) + 13O_2(g)\rightarrow 8CO_2(g) + 10H_2O(l)}; \Delta_c H = -2658.0\mathrm{kJmol^{-1}}\)
B. \(\mathrm{C_4H_{10}(g) + \frac{13}{2}O_2(g)\rightarrow 4CO_2(g) + 5H_2O(g)}; \Delta_c H = -1329.0\mathrm{kJmol^{-1}}\)
C. \(\mathrm{C_4H_{10}(g) + \frac{13}{2}O_2(g)\rightarrow 4CO_2(g) + 5H_2O(l)}; \Delta_c H = -2658.0\mathrm{kJmol^{-1}}\)
D. \(\mathrm{C_4H_{10}(g) + \frac{13}{2}O_2(g)\rightarrow 4CO_2(g) + 5H_2O(l)}; \Delta_c H = +2658.0\mathrm{kJmol^{-1}}\)