A particle crossing the origin of co-ordinates at time \(\mathrm{t} = 0\) moves in the xy-plane with a constant acceleration in the y-direction. If its equation of motion is \(\mathrm{y} = \mathrm{bx}^{2}\) (b is a constant), its velocity component in the x-direction is
Choose Your Option
A. \(\sqrt{\frac{a}{2b}}\)
B. \(\sqrt{\frac{2a}{b}}\)
C. \(\sqrt{\frac{a}{b}}\)
D. \(\sqrt{\frac{b}{a}}\)
Solution & Explanation
No details explanation available for this question. Option A is the verified correct answer.