A conveyor belt is moving at a constant speed of \(2\mathrm{m / s}\) . A box is gently dropped on it. The coefficient of friction between them is \(\mu = 0.5\) . The distance that the box will move relative to belt before coming to rest on it taking \(g = 10\mathrm{m / s}^{-2}\) , is
Choose Your Option
A. \(1.2\mathrm{m}\)
B. \(0.6\mathrm{m}\)
C. zero
D. \(0.4\mathrm{m}\)
Solution & Explanation
No details explanation available for this question. Option D is the verified correct answer.