Real Paper AI
Home
CHEMESTRY
/
Structure of Atom
QID: #28755
The energy of an electron in the \(n^{\mathrm{th}}\) Bohr orbit of hydrogen atom is
Choose Your Option
A.
\(\frac{-13.6}{n^4}\mathrm{eV}\)
B.
\(\frac{-13.6}{n^3}\mathrm{eV}\)
C.
\(\frac{-13.6}{n^2}\mathrm{eV}\)
D.
\(\frac{-13.6}{n}\mathrm{eV}\)
Solution & Explanation
No details explanation available for this question. Option C is the verified correct answer.
Share this Question
WhatsApp
Telegram
Similar Questions
If the nitrogen atom had electronic configuration \(1s^7\...
The five \(d\) orbitals are designated as \(d_{xy}, d_{yz...
The electrons identified by quantum numbers \(n\) and \(l...
An electron has principal quantum number 3. The number of...
Which of the following sets of quantum numbers is correct...