A particle of mass m is projected with a velocity u making an angle of \(30^{\circ}\) with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height \(h\) is
Choose Your Option
A. \(\frac{\sqrt{3}}{2}\frac{mu^2}{g}\)
B. zero
C. \(\frac{mu^3}{\sqrt{2}g}\)
D. \(\frac{\sqrt{3}}{16}\frac{mu^3}{g}\)
Solution & Explanation
No details explanation available for this question. Option D is the verified correct answer.