A block of mass m is placed on a surface with a vertical cross section given by \(\mathrm{y} = \frac{\mathrm{x}^3}{6}\) . If the coefficient of friction is 0.5, the maximum height above the ground at which the block can be placed without slipping is:
Choose Your Option
A. \(\frac{1}{6}\mathrm{m}\)
B. \(\frac{2}{3}\mathrm{m}\)
C. \(\frac{1}{3}\mathrm{m}\)
D. \(\frac{1}{2}\mathrm{m}\)
Solution & Explanation
No details explanation available for this question. Option A is the verified correct answer.